✎ TruMath Assignment

MPM2D Linear Systems
Grade 10 Unit 1 — practice questions with full solutions

Solving two equations at once by graphing, substitution and elimination — plus the word problems that always appear on tests.

Free MPM2D linear systems practice for Grade 10 students in Ontario. These 7 questions cover the same material as a typical unit test or exam review on this topic, and every one comes with a complete worked solution — not just an answer key. Useful whether you are preparing for a MPM2D unit test, catching up on a lesson, or reviewing before the final exam.
MPM2D · Grade 10 Analytic Geometry 6 core 1 challenge
1Core
-2-11234567-4-3-2-1123456xy(2, 1)y = 2x - 3y = -x + 3
Use the graph above to solve the linear system, then verify your answer algebraically in both equations.
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  1. The solution to a system is the point where the lines cross.
  2. Reading the graph, they intersect at (2, 1).
  3. Check in y = 2x − 3: 2(2) − 3 = 1. ✔
  4. Check in y = −x + 3: −(2) + 3 = 1. ✔
  5. Both are satisfied, so (2, 1) is confirmed.
Final answer(2, 1)
2Core
Solve by substitution:   y = 3x − 4   and   2x + y = 11
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  1. The first equation is already solved for y, so substitute it into the second.
  2. 2x + (3x − 4) = 11.
  3. Simplify: 5x − 4 = 11, so 5x = 15 and x = 3.
  4. Substitute back: y = 3(3) − 4 = 5.
Final answer(3, 5)
3Core
Solve by elimination:   3x + 2y = 16   and   5x − 2y = 8
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  1. The y terms are already opposites, so add the two equations directly.
  2. (3x + 5x) + (2y − 2y) = 16 + 8 gives 8x = 24.
  3. So x = 3.
  4. Substitute into the first: 3(3) + 2y = 16, so 2y = 7 and y = 3.5.
Final answer(3, 3.5)
4Core
Solve by elimination:   4x + 3y = 10   and   3x + 5y = 13
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  1. Neither variable eliminates yet, so multiply to match coefficients. Multiply the first by 5 and the second by 3.
  2. 20x + 15y = 50 and 9x + 15y = 39.
  3. Subtract: 11x = 11, so x = 1.
  4. Substitute into 4(1) + 3y = 10: 3y = 6, so y = 2.
Final answer(1, 2)
5Core
Adult tickets cost $12 and student tickets cost $7. A total of 250 tickets were sold for $2400. How many of each were sold?
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  1. Let a be adult tickets and s student tickets.
  2. Ticket count: a + s = 250. Revenue: 12a + 7s = 2400.
  3. From the first, s = 250 − a. Substitute: 12a + 7(250 − a) = 2400.
  4. Expand: 12a + 1750 − 7a = 2400, so 5a = 650 and a = 130.
  5. Then s = 120. Check: 12(130) + 7(120) = 1560 + 840 = 2400. ✔
Final answer130 adult, 120 student
6Core
A canoe travels 24 km downstream in 2 hours and the same 24 km upstream in 3 hours. Find the speed of the canoe in still water and the speed of the current.
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  1. Let c be the canoe speed and r the current speed.
  2. Downstream the speeds add: c + r = 24 ÷ 2 = 12.
  3. Upstream they subtract: cr = 24 ÷ 3 = 8.
  4. Add the two equations: 2c = 20, so c = 10.
  5. Then r = 12 − 10 = 2.
Final answercanoe 10 km/h, current 2 km/h
7Challenge
For what value of k does the system   2x + 3y = 7   and   6x + ky = 21   have infinitely many solutions?
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  1. Infinitely many solutions means the two equations describe the same line.
  2. Compare the x terms: 6 ÷ 2 = 3, so the second equation must be exactly 3 times the first.
  3. Check the constants: 3 × 7 = 21. ✔ This is consistent.
  4. So the y term must satisfy k = 3 × 3 = 9.
  5. Note that if the constant had not matched, no value of k would work — the lines would be parallel instead.
Final answerk = 9

MPM2D Linear Systems — common questions

Short answers to the things students ask most about this unit.

Should I use substitution or elimination?

Use substitution when one equation is already solved for a variable, or easily can be. Use elimination when the equations are both in standard form and coefficients line up.

What does it mean if a system has no solution?

The lines are parallel — same slope, different intercept — so they never cross. If both equations describe the same line, there are infinitely many solutions instead.

Practice is step one

The classes teach the method behind every one of these.

The solutions above show the steps. The classes teach how to think about the problem in the first place — interactive, and worked through at the student’s own pace. Try 3 complete classes free — no payment required to begin.

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